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2013
11-09

POJ 1300 Door Man [解题报告] Java

Door Man

问题描述 :

You are a butler in a large mansion. This mansion has so many rooms that they are merely referred to by number (room 0, 1, 2, 3, etc…). Your master is a particularly absent-minded lout and continually leaves doors open throughout a particular floor of the house. Over the years, you have mastered the art of traveling in a single path through the sloppy rooms and closing the doors behind you. Your biggest problem is determining whether it is possible to find a path through the sloppy rooms where you:
  1. Always shut open doors behind you immediately after passing through
  2. Never open a closed door
  3. End up in your chambers (room 0) with all doors closed

In this problem, you are given a list of rooms and open doors between them (along with a starting room). It is not needed to determine a route, only if one is possible.

输入:

Input to this problem will consist of a (non-empty) series of up to 100 data sets. Each data set will be formatted according to the following description, and there will be no blank lines separating data sets.

A single data set has 3 components:
  1. Start line – A single line, “START M N”, where M indicates the butler’s starting room, and N indicates the number of rooms in the house (1 <= N <= 20).
  2. Room list – A series of N lines. Each line lists, for a single room, every open door that leads to a room of higher number. For example, if room 3 had open doors to rooms 1, 5, and 7, the line for room 3 would read “5 7″. The first line in the list represents room 0. The second line represents room 1, and so on until the last line, which represents room (N – 1). It is possible for lines to be empty (in particular, the last line will always be empty since it is the highest numbered room). On each line, the adjacent rooms are always listed in ascending order. It is possible for rooms to be connected by multiple doors!
  3. End line – A single line, “END”

Following the final data set will be a single line, “ENDOFINPUT”.

Note that there will be no more than 100 doors in any single data set.

输出:

For each data set, there will be exactly one line of output. If it is possible for the butler (by following the rules in the introduction) to walk into his chambers and close the final open door behind him, print a line “YES X”, where X is the number of doors he closed. Otherwise, print “NO”.

样例输入:

START 1 2
1

END
START 0 5
1 2 2 3 3 4 4




END
START 0 10
1 9
2
3
4
5
6
7
8
9

END
ENDOFINPUT

样例输出:

YES 1
NO
YES 10

解题代码:

//* @author: [email protected]
import java.util.Scanner;
public class Main
{
	
public static void main(String[] args)
{
  Scanner in=new Scanner(System.in);
  while(true)
  {
	String s=in.next();
	if(s.equals("ENDOFINPUT"))break;
	int loc=in.nextInt();
	int n=in.nextInt();
	in.nextLine();
	int[] door=new int[n];
	int doors=0;
	for(int i=0;i< n;i++)
	{
		s=in.nextLine();
		if(s.equals("")) continue;
		String[] ss=s.split(" ");
		for(int j=0;j< ss.length;j++)
		{
			int u=Integer.parseInt(ss[j]);
			door[i]++;
			door[u]++;
			doors++;
		}
	}
	s=in.nextLine();
	int odd=0,even=0;
	for(int i=0;i< n;i++)
	{
		if(door[i]%2==0) even++;
		else odd++;
	}
	if(odd==0&&loc==0) System.out.println("YES "+doors);
	else if(odd==2&&loc!=0&&door[loc]%2==1&&door[0]%2==1)
		System.out.println("YES "+doors);
	else System.out.println("NO");
  }
 }
}

  1. 第一句可以忽略不计了吧。从第二句开始分析,说明这个花色下的所有牌都会在其它里面出现,那么还剩下♠️和♦️。第三句,可以排除2和7,因为在两种花色里有。现在是第四句,因为♠️还剩下多个,只有是♦️B才能知道答案。