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2013
11-10

POJ 1740 A New Stone Game [解题报告] Java

A New Stone Game

问题描述 :

Alice and Bob decide to play a new stone game.At the beginning of the game they pick n(1<=n<=10) piles of stones in a line. Alice and Bob move the stones in turn.

At each step of the game,the player choose a pile,remove at least one stones,then freely move stones from this pile to any other pile that still has stones.

For example:n=4 and the piles have (3,1,4,2) stones.If the player chose the first pile and remove one.Then it can reach the follow states.

2 1 4 2

1 2 4 2(move one stone to Pile 2)

1 1 5 2(move one stone to Pile 3)

1 1 4 3(move one stone to Pile 4)

0 2 5 2(move one stone to Pile 2 and another one to Pile 3)

0 2 4 3(move one stone to Pile 2 and another one to Pile 4)

0 1 5 3(move one stone to Pile 3 and another one to Pile 4)

0 3 4 2(move two stones to Pile 2)

0 1 6 2(move two stones to Pile 3)

0 1 4 4(move two stones to Pile 4)

Alice always moves first. Suppose that both Alice and Bob do their best in the game.

You are to write a program to determine who will finally win the game.

输入:

The input contains several test cases. The first line of each test case contains an integer number n, denoting the number of piles. The following n integers describe the number of stones in each pile at the beginning of the game, you may assume the number of stones in each pile will not exceed 100.

The last test case is followed by one zero.

输出:

For each test case, if Alice win the game,output 1,otherwise output 0.

样例输入:

3
2 1 3
2
1 1
0

样例输出:

1
0

解题代码:

/* @author: */
import java.util.Scanner;
public class Main{
 public static void main(String args[]){
 Scanner sc=new Scanner(System.in);
 int a[]=new int[11];
 boolean flag=false;
 while(sc.hasNext())
 {
  flag=true;
  int n=sc.nextInt();
  if(n==0)
    break;
  for(int i=1;i<=n;i++)
   a[i]=sc.nextInt();
   if(n%2==1)
    {
      System.out.printf("1\n");
      continue;
    }//如果是奇数,则必然是第一个人赢
    for(int i=1;i< n&&flag;i++)
     {
      for(int j=i+1;j<=n&&flag;j++)
        if(a[i]!=0&&a[i]==a[j]){
         a[i]=0;
         a[j]=0;
         break;
        }
     
        if(a[i]!=0) flag=false;
     }//如果是偶数,则判断是否成双成对
    if(!flag)
      System.out.printf("1\n");
    else System.out.printf("0\n");
 }
}
}

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