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2013
11-11

POJ 2316 SPIN [解题报告] Java

SPIN

问题描述 :

Simulate a locked spinner puzzle.

A locked spinner puzzle is a puzzle where you can only change wheels in groups. It is a common puzzle to achieve some value on the spinners by only changing them in the allowed groups.

Imagine a row of D numbered wheels, each labeled sequentially with the digits 0 through 9. This is similar to what is on a briefcase combination lock.

Below this are a series of B buttons with labels that are D digits long. For example, D may be 4 and the labels are 1000 1200 1002 0111 and 0100. Pressing the button labeled 1000 moves the first wheel once, but leaves the others alone, while pressing the button labeled 1002 moves the first wheel once and the fourth wheel twice, leaving the center wheels unchanged.

Your task is to simulate such a locked spinner puzzle giving the final readout of the wheels.

输入:

The input to your program will be a line containing D digits (at most 10) representing the starting positions of the wheels. Following this, each line will have the button label for which button is pressed next.There will always be at least 1 digit

输出:

Output the final positions of the wheels.

样例输入:

0001
1003
0206
0034
1111
1003

样例输出:

3348

解题代码:

//* @author: 82638882@163.com
import java.util.Scanner;
public class Main
{
 public static void main(String[] args)
 {
  Scanner in=new Scanner(System.in);
  int[] a=new int[300];
  int k=0;
  while(in.hasNextInt())
  {
		
   String s=in.next();
   for(int i=0;i< s.length();i++)
	a[i]=(a[i]+s.charAt(i)-'0')%10;
   k=s.length();
  }
  for(int i=0;i< k;i++)
  {
   System.out.print(a[i]);
  }
 }
}

  1. #!/usr/bin/env python
    def cou(n):
    arr =
    i = 1
    while(i<n):
    arr.append(arr[i-1]+selfcount(i))
    i+=1
    return arr[n-1]

    def selfcount(n):
    count = 0
    while(n):
    if n%10 == 1:
    count += 1
    n /= 10
    return count

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