2013
11-13

# Election Time

The cows are having their first election after overthrowing the tyrannical Farmer John, and Bessie is one of N cows (1 ≤ N ≤ 50,000) running for President. Before the election actually happens, however, Bessie wants to determine who has the best chance of winning.

The election consists of two rounds. In the first round, the K cows (1 ≤ KN) cows with the most votes advance to the second round. In the second round, the cow with the most votes becomes President.

Given that cow i expects to get Ai votes (1 ≤ Ai ≤ 1,000,000,000) in the first round and Bi votes (1 ≤ Bi ≤ 1,000,000,000) in the second round (if he or she makes it), determine which cow is expected to win the election. Happily for you, no vote count appears twice in the Ai list; likewise, no vote count appears twice in the Bi list.

* Line 1: Two space-separated integers: N and K
* Lines 2..N+1: Line i+1 contains two space-separated integers: Ai and Bi

* Line 1: The index of the cow that is expected to win the election.

5 3
3 10
9 2
5 6
8 4
6 5


5


//* @author 洪晓鹏<hongxp11@163.com>
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.Scanner;

public class Main {
static class vote {
int first;
int second;
int index;
}

public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int N = in.nextInt();
int K = in.nextInt();
// vote[] voters = new vote[N];
ArrayList< vote> voters = new ArrayList< vote>();
for (int i = 0; i < N; i++) {
vote temp = new vote();
temp.first = in.nextInt();
temp.second = in.nextInt();
temp.index = i + 1;
}
Collections.sort(voters, new Comparator< Object>() {
public int compare(Object o1, Object o2) {
vote a = (vote) o1;
vote b = (vote) o2;
return b.first - a.first;
}

});

int result = 0;
for (int i = 1; i < K; i++) {
if (voters.get(result).second < voters.get(i).second) {

result = i;
}
}
System.out.println(voters.get(result).index);
}
}

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