2013
11-27

# HDU 1133 Buy the Ticket-动态规划-[解题报告] java

The "Harry Potter and the Goblet of Fire" will be on show in the next few days. As a crazy fan of Harry Potter, you will go to the cinema and have the first sight, won’t you?

Suppose the cinema only has one ticket-office and the price for per-ticket is 50 dollars. The queue for buying the tickets is consisted of m + n persons (m persons each only has the 50-dollar bill and n persons each only has the 100-dollar bill).

Now the problem for you is to calculate the number of different ways of the queue that the buying process won’t be stopped from the first person till the last person.
Note: initially the ticket-office has no money.

The buying process will be stopped on the occasion that the ticket-office has no 50-dollar bill but the first person of the queue only has the 100-dollar bill.

The input file contains several test cases. Each test case is made up of two integer numbers: m and n. It is terminated by m = n = 0. Otherwise, m, n <=100.

For each test case, first print the test number (counting from 1) in one line, then output the number of different ways in another line.

3 0
3 1
3 3
0 0

Test #1:
6
Test #2:
18
Test #3:
180

import java.util.*;
import java.math.*;
public class Main {

/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner cin = new Scanner(System.in);
BigInteger dp[][] = new BigInteger[109][109] ;

int a,b;
int T = 1;
while(true){
a = cin.nextInt();b=cin.nextInt();
int ta =a,tb = b;
if(a==0&&b==0) break;
for(int i=0;i<109;i++)
for(int j=0;j<109;j++) dp[i][j] = BigInteger.ZERO;
System.out.println("Test #"+T+":");T++;
if(a<b){
System.out.println("0");
continue;
}
dp[0][0] = BigInteger.ONE;
for(int j=1;j<=a;j++)
{dp[0][j] = dp[0][j-1].multiply(BigInteger.valueOf(ta));ta--;}
for(int i=1;i<=b;i++){
for(int j=i;j<=a;j++){
dp[i][j]=dp[i-1][j].multiply(BigInteger.valueOf(b+1-i));
}