2013
12-04

# Cube

Cowl is good at solving math problems. One day a friend asked him such a question: You are given a cube whose edge length is N, it is cut by the planes that was paralleled to its side planes into N * N * N unit cubes. Two unit cubes may have no common points or two common points or four common points. Your job is to calculate how many pairs of unit cubes that have no more than two common points.

Process to the end of file.

There will be many test cases. Each test case will only give the edge length N of a cube in one line. N is a positive integer(1<=N<=30).

For each test case, you should output the number of pairs that was described above in one line.

1
2
3

0
16
297

HintHint
The results will not exceed int type.

//数学，没化简，直接用
#include <cstdio>
#include <iostream>

using namespace std;

int main() {
int n;
while (scanf("%d", &n) != EOF) {
int s = n * n * n;
int ans = (s-4)*4 + 6*(n-2)*(s-5) + 3*(n-2)*(n-2)*(s-6) + (n-2)*(n-2)*(n-2)*(s-7)/2;
printf ("%d\n", ans);
}
return 0;
}

1. 本来已经在最大负重附近的了，左脚踏在中间部分，最后有个前倾的动作，让左脚的压力增加到了突破上限，于是遮阳棚发生折叠