首页 > ACM题库 > HDU-杭电 > Hdu 1442 Soundex Indexing-字符串[解题报告] C++
2013
12-10

Hdu 1442 Soundex Indexing-字符串[解题报告] C++

Soundex Indexing

问题描述 :

The Soundex Index System was developed so that similar sounding names, or names with similar spelling could be encoded for easy retrieval. It has been used by the U.S. Bureau of the Census, and some States use it to help encode your driver’s license number. Your task is to read a sequence of names, one at a time and one per line, compute the corresponding soundex code, and write to the output file the name and its soundex code (one line of output per name).

Names will contain from 1 to 20 upper case, alphabetic characters (ASCII values 65 thru 90, inclusive). Names shorter than 20 characters will NOT be padded with blanks. Thus a narne will consist of upper case letters only.

How to generate the Soundex Code:
A Soundex Code always consists of a letter followed by three digits. Here are the rules for soundex encoding:

1. The first letter of a name appears as the first and only letter in the soundex code.
2. The letters A, E, I, O, U, Y, W, & H are never encoded, but do break successive code sequences (see next rule).
3. All other letters are encoded EXCEPT when they immediately follow a letter (including the first letter) that would be encoded with the same code digit.
4. The soundex code guide is:

5. Trailing zeros are appended to short codes so all names are encoded with a letter followed by three digits.
6. Longer codes are truncated after the third digit.

输入:

The input file, SOUNDEX.IN, contains a list of names, one per line. Each name will not exceed 20 characters, and you may assume that only upper case letters will be used. Your program should continue to read names until the end of the file is detected.

输出:

The output written to the file SOUNDEX.OUT should consist of a column of names and a column of their corresponding soundex codes. Write the headings “NAME” and “SOUNDEX CODE” in the first line of the output file in columns 10 and 35, respectively. After the heading line, the names and soundex codes should be written (one pair per line) with the name starting in column 10 and the soundex code beginning in column 35. The comment “END OF OUTPUT” should appear at the end of the output file on the line immediately after the last name. This comment should be written starting in column 20.

样例输入:

LEE
KUHNE
EBELL
EBELSON
SCHAEFER
SCHAAK

样例输出:

         NAME                     SOUNDEX CODE
         LEE                      L000
         KUHNE                    K500
         EBELL                    E140
         EBELSON                  E142
         SCHAEFER                 S160
         SCHAAK                   S200
                   END OF OUTPUT
         |         |              |
         |         |              |__ Column 35
         |         |__ Column 20
         |__ Column 10


这个题目是让我比较蛋疼的,
提交了很多次都没有通过最后原来是
END OF OUTPUT后面忘了加上换行号

#include<cstdio>
#include<cstring>
using namespace std;
char name[30];
int getcode(char c)
{
	switch (c)
	{
	case 'B':
	case 'p':
	case 'F':
	case 'V':
		return 1;
		break;
	case 'C':
	case 'S':
	case 'K':
	case 'G':
	case 'J':
	case 'Q':
	case 'X':
	case 'Z':
		return 2;
		break;
	case 'D':
	case 'T':
		return 3;
		break;
	case 'L':
		return 4;
		break;
	case 'M':
	case 'N':
		return 5;
		break;
	case 'R':
		return 6;
		break;
	default:
		return 0;
	}
}

int main()
{
//freopen("in.txt","r",stdin);
//freopen("out.txt","w",stdout);
	for (int i = 1; i <= 9; i++)
		printf(" ");
	printf("NAME");
	for (int i = 14; i <= 34; i++)
		printf(" ");
	printf("SOUNDEX CODE\n");
	while (scanf("%s", name) == 1)
	{
		int u = 0;
		int v = 0;
		int t = 0;
		for (int i = 1; i <= 9; i++)
			printf(" ");
		printf("%s", name);
		for (int i = 10 + strlen(name); i <= 34; i++)
			printf(" ");
		printf("%c", name[0]);
		for (int i = 1; name[i] != '\0'; i++)
		{
			if (u != 0 && v != 0 && t != 0)
				break;
			switch (name[i])
			{
			case 'A':
			case 'E':
			case 'I':
			case 'O':
			case 'U':
			case 'Y':
			case 'W':
			case 'H':
//continue;
				break;
			default:
				if (!u)
				{
					if (getcode(name[i - 1]) == getcode(name[i]))
						break;
					u = getcode(name[i]);
				}
				else if (!v)
				{
					if (getcode(name[i - 1]) == getcode(name[i]))
						break;
					v = getcode(name[i]);
				}
				else
				{
					if (getcode(name[i - 1]) == getcode(name[i]))
						break;
					t = getcode(name[i]);
				}
			}
		}
		printf("%d%d%d\n", u, v, t);
	}
	for (int i = 1; i <= 19; i++)
		printf(" ");
	printf("END OF OUTPUT\n");
	return 0;
}

转自:http://blog.csdn.net/hechenghai/article/details/6745964


  1. 其实国内大部分公司对算法都不够重视。特别是中小型公司老板根本都不懂技术,也不懂什么是算法,从而也不要求程序员懂什么算法,做程序从来不考虑性能问题,只要页面能显示出来就是好程序,这是国内的现状,很无奈。

  2. int half(int *array,int len,int key)
    {
    int l=0,r=len;
    while(l<r)
    {
    int m=(l+r)>>1;
    if(key>array )l=m+1;
    else if(key<array )r=m;
    else return m;
    }
    return -1;
    }
    这种就能避免一些Bug
    l,m,r
    左边是l,m;右边就是m+1,r;