2014
03-16

Probability One

Number guessing is a popular game between elementary-school kids. Teachers encourage pupils to play the game as it enhances their arithmetic skills, logical thinking, and following-up simple procedures. We think that, most probably, you too will master in few minutes. Here’s one example of how you too can play this game: Ask a friend to think of a number, let’s call it n0.
Then:
1. Ask your friend to compute n1 = 3 * n0 and to tell you if n1 is even or odd.
2. If n1 is even, ask your friend to compute n2 = n1/2. If, otherwise, n1 was odd then let your friend compute n2 = (n1 + 1)/2.
3. Now ask your friend to calculate n3 = 3 * n2.
4. Ask your friend to tell tell you the result of n4 = n3/9. (n4 is the quotient of the division operation. In computer lingo, ’/’ is the integer-division operator.)
5. Now you can simply reveal the original number by calculating n0 = 2 * n4 if n1 was even, or n0 = 2 * n4 + 1 otherwise.
Here’s an example that you can follow: If n0 = 37, then n1 = 111 which is odd. Now we can calculate n2 = 56, n3= 168, and n4 = 18, which is what your friend will tell you. Doing the calculation 2 × n4 + 1 = 37 reveals n0.

Your program will be tested on one or more test cases. Each test case is made of a single positive number (0 < n0 < 1, 000, 000).
The last line of the input file has a single zero (which is not part of the test cases.)

Your program will be tested on one or more test cases. Each test case is made of a single positive number (0 < n0 < 1, 000, 000).
The last line of the input file has a single zero (which is not part of the test cases.)

37
38
0

1. odd 18
2. even 19

#include<stdio.h>
int main()
{
int n0;
int iCase=0;
while(scanf("%d",&n0),n0)
{
iCase++;
printf("%d. ",iCase);
if(n0%2==0)
printf("even %d\n",n0/2);
else
printf("odd %d\n",(n0-1)/2);
}
return 0;
}

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