2015
09-16

# X-Boxes

Crazygirl is a crazy fan of XBOX games. Today, she’s here middle in a competition, in which the winner will be rewarded with an opportunity of working in the XBOX Company as a game testing player. Now, here comes the final game. As Cazygirl get a draw with the other competitor, Lich King, she must beat Lich this time.
The game is quite simple. There are n balls numbered from 1 to n and k boxes B1, B2,…, Bk satisfying following conditions:
1.  With any ball x in box Bi, there must be ball 2x in box Bi+1 if there is a box Bi+1;
2.  With any ball x in box Bi, there must be ball y in box Bi-1 satisfying 2y=x if there is a box Bi-1;
3.  You can’t put a ball in two different boxes at the same time;
4.  Your score is the number of balls in box B1;
5.  The player who get the highest score win the game of course.
So, you should tell Crazygirl the highest score she can get.

The first line is the number of test cases.
Each test case has one line containing two integers n and k, meaning that there are n balls and k boxes. ( 1≤n≤1010000, 2≤k≤25 )

The first line is the number of test cases.
Each test case has one line containing two integers n and k, meaning that there are n balls and k boxes. ( 1≤n≤1010000, 2≤k≤25 )

3
10 2
7 5
8 3

4
0
1

import java.util.*;
import java.math.*;
public class Main {
public static void main(String[] args) {
BigInteger s,n,tmp;int k;
int cas;
Scanner cin = new Scanner(System.in);
cas = cin.nextInt();
while(cas>0){ cas--;
n = cin.nextBigInteger();
k = cin.nextInt();
s = BigInteger.ZERO;
int cc = 1;
for(int i=1;i<k;i++){
cc*=2;
}
while(1==1){
n = n.divide(BigInteger.valueOf(cc));
tmp = n.subtract(n.divide(BigInteger.valueOf(2)));
if(tmp.equals(BigInteger.ZERO)) break;
s = s.add(tmp);
n = n.divide(BigInteger.valueOf(2));
}
System.out.println(s);
}
}
}