2015
09-17

# A Computer Graphics Problem

In this problem we talk about the study of Computer Graphics. Of course, this is very, very hard.
We have designed a new mobile phone, your task is to write a interface to display battery powers.
Here we use ‘.’ as empty grids.
When the battery is empty, the interface will look like this:
*------------*|............||............||............||............||............||............||............||............||............||............|*------------*

When the battery is 60% full, the interface will look like this:

*------------*|............||............||............||............||------------||------------||------------||------------||------------||------------|*------------*

Each line there are 14 characters.
Given the battery power the mobile phone left, say x%, your task is to output the corresponding interface. Here x will always be a multiple of 10, and never exceeds 100.

The first line has a number T (T < 10) , indicating the number of test cases.
For each test case there is a single line with a number x. (0 < x < 100, x is a multiple of 10)

The first line has a number T (T < 10) , indicating the number of test cases.
For each test case there is a single line with a number x. (0 < x < 100, x is a multiple of 10)

2
0
60

Case #1:
*------------*
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
|............|
*------------*
Case #2:
*------------*
|............|
|............|
|............|
|............|
|------------|
|------------|
|------------|
|------------|
|------------|
|------------|
*------------*

AC代码：

#include <cstdio>
#include <cstring>

int main() {
int t,flag = 0;
scanf("%d", &t);
while(t--) {
int x;
scanf("%d", &x);
printf("Case #%d:\n", ++flag);
if(x==0) {
puts("*------------*");
for(int i=0; i<10; i++)
puts("|............|");
puts("*------------*");
}
else {
int p = x/10;
puts("*------------*");
for(int i=0; i<(10-p); i++) {
puts("|............|");
}
for(int i=0; i<p; i++) {
puts("|------------|");
}
puts("*------------*");
}
}
return 0;
}