首页 > ACM题库 > HDU-杭电 > HDU 4730-We Love MOE Girls-字符串-[解题报告]HOJ
2015
09-17

HDU 4730-We Love MOE Girls-字符串-[解题报告]HOJ

We Love MOE Girls

问题描述 :

Chikami Nanako is a girl living in many different parallel worlds. In this problem we talk about one of them.
In this world, Nanako has a special habit. When talking with others, she always ends each sentence with "nanodesu".
There are two situations:
If a sentence ends with "desu", she changes "desu" into "nanodesu", e.g. for "iloveyoudesu", she will say "iloveyounanodesu". Otherwise, she just add "nanodesu" to the end of the original sentence.
Given an original sentence, what will it sound like aften spoken by Nanako?

输入:

The first line has a number T (T <= 1000) , indicating the number of test cases.
For each test case, the only line contains a string s, which is the original sentence.
The length of sentence s will not exceed 100, and the sentence contains lowercase letters from a to z only.

输出:

The first line has a number T (T <= 1000) , indicating the number of test cases.
For each test case, the only line contains a string s, which is the original sentence.
The length of sentence s will not exceed 100, and the sentence contains lowercase letters from a to z only.

样例输入:

2
ohayougozaimasu
daijyoubudesu

样例输出:

Case #1: ohayougozaimasunanodesu
Case #2: daijyoubunanodesu

字符串处理  输出

AC代码:

#include <stdio.h>
#include <string.h>

int main() {
    char a[120];
    int t, tt = 0;
    scanf("%d", &t);
    while(t--) {
        scanf("%s", a);
        printf("Case #%d: ", ++tt);
        int len = strlen(a);
        if(a[len-1] == 'u' && a[len-2] == 's' && a[len-3] == 'e' && a[len-4] == 'd' &&
           a[len-5] == 'o' && a[len-6] == 'n' && a[len-7] == 'a' && a[len-8] == 'n') {
            printf("%s", a);
        }
        else if(a[len-1] == 'u' && a[len-2] == 's' && a[len-3] == 'e' && a[len-4] == 'd') {
            for(int i=0; i<len-4; i++) {
                printf("%c", a[i]);
            }
            printf("nanodesu\n");
        }
        else {
            printf("%s", a);
            printf("nanodesu\n");
        }
    }
    return 0;
}

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参考:http://blog.csdn.net/chuck_0430/article/details/11689225